In the esterification reaction of p-toluic ac | vedclass

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(A) The esterification of a carboxylic acid with an alcohol proceeds via an $A_{AC}2$ mechanism. In this mechanism,the alcohol acts as a nucleophile a

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(A) The esterification of a carboxylic acid with an alcohol proceeds via an $A_{AC}2$ mechanism. In this mechanism,the alcohol acts as a nucleophile and attacks the carbonyl carbon of the protonated carboxylic acid. The bond between the acyl carbon and the hydroxyl group of the acid is cleaved,and the oxygen atom from the alcohol is incorporated into the ester. Therefore,when $p$-toluic acid reacts with methanol labeled with $^{18}O$ $(CH_3^{18}OH)$,the $^{18}O$ atom ends up in the alkoxy part of the ester,forming $p-CH_3-C_6H_4-CO-^{18}OCH_3$.

In the esterification reaction of $p$-toluic acid with methanol $(CH_3^{18}OH)$,the product $A$ is:

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