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(B) When a stimulus is applied to a site on the polarized membrane,the permeability of the membrane to $Na^+$ ions increases rapidly.This leads to a m

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More sodium ions enter the nerve fiber than potassium ions leave.

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(B) When a stimulus is applied to a site on the polarized membrane,the permeability of the membrane to $Na^+$ ions increases rapidly.This leads to a massive influx of $Na^+$ ions into the axon from the extracellular fluid.As a result,the inner side of the membrane becomes positively charged relative to the outer side,which is known as depolarization.This rapid influx of $Na^+$ ions is significantly greater than the efflux of $K^+$ ions,causing the reversal of polarity (action potential).

An action potential in a nerve fiber is generated when the $+ve$ and $-ve$ charges on the outside and inside of the axon membrane are reversed because ...........

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What is the value of the resting membrane potential in a neuron (in $, mV$)?

For the propagation of a nerve impulse along a nerve fiber,what is the sequence of change in the electrical potential difference across the axolemma?

$A$ nerve impulse will travel through a nerve fibre only if the membrane suddenly becomes more permeable to

Assertion $(A)$: The axonal membrane of the neuron is more permeable to sodium ion $(Na^+)$ and nearly impermeable to potassium $(K^+)$.
Reason $(R)$: In a resting state,a neuron does not conduct any impulse.

Which of the following statements is/are correct?
$(a)$ The electrical potential difference across the resting plasma membrane is called the resting potential.
$(b)$ $Na^+$ ions are responsible for the generation of an action potential.
$(c)$ $A$ nerve impulse is an action potential.

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