The propagation of an action potential during nerve impulse conduction is made possible by the movement of:

  • A
    $K^+$ ions from extracellular fluid to intracellular fluid
  • B
    $Na^+$ ions from intracellular fluid to extracellular fluid
  • C
    $K^+$ ions from intracellular fluid to extracellular fluid
  • D
    $Na^+$ ions from extracellular fluid to intracellular fluid

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Similar Questions

How does the conduction of a nerve impulse occur?

$A$ nerve impulse is defined as .........

The depolarization of nerve membrane takes place through influx of . . . . . . ions.

Assertion $(A)$: The axonal membrane of the neuron is more permeable to sodium ion $(Na^+)$ and nearly impermeable to potassium $(K^+)$.
Reason $(R)$: In a resting state,a neuron does not conduct any impulse.

Which of the following statement/s is/are correct with respect to generation and conduction of nerve impulse?
i. The resting potential difference is $-70 \text{ mV}$.
ii. The voltage-gated $Na^{+}$ and $K^{+}$ channels operate together and are self-closing.
iii. At the peak of action potential,the potential difference rises to $+30$ to $+60 \text{ mV}$.
iv. In medullated nerve fibre,the action potential is conducted as a wave of membrane depolarization.
v. The resting potential is maintained by the closure of gated channels of $Na^{+}$ and $K^{+}$.

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