$A$ $Ge$ specimen is doped with $Al$. The concentration of acceptor atoms is $\sim 10^{21} \, \text{atoms}/m^3$. Given that the intrinsic concentration of electron-hole pairs is $\sim 10^{19}/m^3$, the concentration of electrons in the specimen is:
- A$10^{17}/m^3$
- B$10^{15}/m^3$
- C$10^4/m^3$
- D$10^2/m^3$
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