A 200 g golf ball is moving with a speed of | vedclass

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(C) According to the de Broglie equation,$\lambda = \frac{h}{mv}$.Given: $h = 6.625 	imes 10^{-34} \ J \ s$,$m = 200 \ g = 0.2 \ kg$,and $v = 5 \ m/h

Vedclass · Accepted Answer

$10^{-30} \ m$

Vedclass · Answer

(C) According to the de Broglie equation,$\lambda = \frac{h}{mv}$.Given: $h = 6.625 	imes 10^{-34} \ J \ s$,$m = 200 \ g = 0.2 \ kg$,and $v = 5 \ m/h = \frac{5}{3600} \ m/s$.Substituting the values:$\lambda = \frac{6.625 	imes 10^{-34}}{0.2 	imes (5 / 3600)} = \frac{6.625 	imes 10^{-34}}{1 / 3600} = 6.625 	imes 10^{-34} 	imes 3600 \approx 2.385 	imes 10^{-30} \ m$.Rounding to the nearest order of magnitude,the answer is $10^{-30} \ m$.

$A$ $200 \ g$ golf ball is moving with a speed of $5 \ m$ per hour. The associated wavelength is $(h = 6.625 \times 10^{-34} \ J \ s)$.

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