A 1000 g sample of NaOH contains 3 moles of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The chemical formula of $NaOH$ is $NaOH$. One mole of $NaOH$ contains $1 \ mole$ of $O$ atoms.Given that the sample contains $3 \ moles$ of $O$ at

Vedclass · Accepted Answer

$12$

Vedclass · Answer

(C) The chemical formula of $NaOH$ is $NaOH$. One mole of $NaOH$ contains $1 \ mole$ of $O$ atoms.Given that the sample contains $3 \ moles$ of $O$ atoms,the amount of pure $NaOH$ is $3 \ moles$.The molar mass of $NaOH$ is $23 + 16 + 1 = 40 \ g/mol$.Mass of pure $NaOH = 3 \ mol 	imes 40 \ g/mol = 120 \ g$.Percentage purity = $\frac{	ext{Mass of pure } NaOH}{	ext{Total mass of sample}} 	imes 100$.Percentage purity = $\frac{120 \ g}{1000 \ g} 	imes 100 = 12 \%$.

$A$ $1000 \ g$ sample of $NaOH$ contains $3 \ moles$ of $O$ atoms. What is the $Purity$ of $NaOH$ $\dots \dots \dots \dots \dots \dots \%$

Similar Questions

The molecular mass of an organic monobasic acid is $129$ and the value of $n$ is $2$. What is the empirical formula mass of the compound?

How many grams of oxygen are present in $32.2 \ g$ of $Na_2SO_4 \cdot 10H_2O$ (in $g$)?

$A$ transition metal $M$ forms a volatile chloride which has a vapour density of $94.8$. If it contains $74.75\%$ of chlorine,the formula of the metal chloride will be:

One compound contains $4.07\%$ Hydrogen,$24.47\%$ Carbon and $71.65\%$ Chlorine. Its molar mass is $98.96\ g/mol$. Find the empirical formula and molecular formula.

When a crystalline salt $Na_2SO_4 \cdot xH_2O$ is heated,it loses $55.9\%$ of its weight. What is the formula of the crystalline salt?

Vedclass Test Series

Exam Paper Generator

Online Exam Module