(B) In a parallel circuit,the voltage across each component is the same as the battery voltage.Voltage across bulb $1$ $(V_1)$ $= 6.0\,V$.Voltage acro

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(B) In a parallel circuit,the voltage across each component is the same as the battery voltage.Voltage across bulb $1$ $(V_1)$ $= 6.0\,V$.Voltage across bulb $2$ $(V_2)$ $= 6.0\,V$.The brightness of a bulb is determined by the power dissipated,given by $P = \frac{V^2}{R}$.For bulb $1$: $P_1 = \frac{6^2}{3} = \frac{36}{3} = 12\,W$.For bulb $2$: $P_2 = \frac{6^2}{6} = \frac{36}{6} = 6\,W$.Since $P_1 > P_2$,bulb $1$ will glow brighter.

Class 12 Physics Current Electricity Electrical Energy and Power

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$A$ $6.0\,V$ battery is connected to two light bulbs as shown in the figure. Light bulb $1$ has a resistance of $3\,\Omega$ while light bulb $2$ has a resistance of $6\,\Omega$. The battery has negligible internal resistance. Which bulb will glow brighter?

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A
Bulb $1$ will glow more first and then its brightness will become less than bulb $2$
B
Bulb $1$
C
Bulb $2$
D
Both glow equally

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$A$ $6.0\,V$ battery is connected to two light bulbs as shown in the figure. Light bulb $1$ has a resistance of $3\,\Omega$ while light bulb $2$ has a resistance of $6\,\Omega$. The battery has negligible internal resistance. Which bulb will glow brighter?

Similar Questions

$A$ rise of temperature of $4\,^oC$ is observed in a conductor by passing a current. If the current is tripled,the rise in temperature will be .............. $^oC$.

An electric room radiator which operates at $225\, V$ has a resistance of $50\, \Omega$. The power of the radiator is approximately ............... $W$.

Explain electrical energy and power.

Water boils in an electric kettle in $20$ minutes after being switched on. Using the same main supply,the length of the heating element should be . . . . . . to . . . . . . times of its initial length if the water is to be boiled in $15$ minutes.

Two electric bulbs have resistances in the ratio $1 : 2$. If they are connected in parallel to a constant voltage source,the ratio of power dissipated in them will be:

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