A 60; mu F capacitor is connected to a 110; V | vedclass

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(C) Given: Capacitance $C = 60\; \mu F = 60 	imes 10^{-6}\; F$,Voltage $V_{rms} = 110\; V$,Frequency $f = 60\; Hz$.The capacitive reactance $X_C$ is

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$2.5$

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(C) Given: Capacitance $C = 60\; \mu F = 60 	imes 10^{-6}\; F$,Voltage $V_{rms} = 110\; V$,Frequency $f = 60\; Hz$.The capacitive reactance $X_C$ is given by the formula $X_C = \frac{1}{2\pi f C}$.Substituting the values: $X_C = \frac{1}{2 	imes 3.1416 	imes 60 	imes 60 	imes 10^{-6}}$.$X_C = \frac{1}{0.022619} \approx 44.21\; \Omega$.The $rms$ current $I_{rms}$ is given by $I_{rms} = \frac{V_{rms}}{X_C}$.$I_{rms} = \frac{110}{44.21} \approx 2.488\; A$.Rounding to one decimal place,we get $I_{rms} \approx 2.5\; A$.

$A$ $60\; \mu F$ capacitor is connected to a $110\; V, 60\; Hz$ $ac$ supply. Determine the $rms$ value of the current in the circuit. (in $; A$)

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