A 0.3 , M HCl solution contains the following | vedclass

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(A) In a $0.3 \, M$ $HCl$ solution,the concentration of $S^{2-}$ ions is very low due to the common ion effect of $H^+$ ions from $HCl$,which suppress

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$Cd^{2+}, Cu^{2+}, Hg^{2+}$

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(A) In a $0.3 \, M$ $HCl$ solution,the concentration of $S^{2-}$ ions is very low due to the common ion effect of $H^+$ ions from $HCl$,which suppresses the dissociation of $H_2S$.Only the sulfides of the Group $II$ basic radicals,which have very low solubility products $(K_{sp})$,will precipitate under these conditions.Among the given ions,$Hg^{2+}, Cd^{2+},$ and $Cu^{2+}$ belong to Group $II$,while $Fe^{2+}$ and $Sr^{2+}$ do not precipitate in acidic medium.Therefore,$Hg^{2+}, Cd^{2+},$ and $Cu^{2+}$ will precipitate as their respective sulfides.

$A$ $0.3 \, M$ $HCl$ solution contains the following ions: $Hg^{2+}, Cd^{2+}, Sr^{2+}, Fe^{2+}, Cu^{2+}$. The addition of $H_2S$ to the above solution will precipitate which of the following?

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