A 180, m long train crosses another 270, m lo | vedclass

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(B) Let the speed of the second train be $x\, km/h$.Since the trains are moving in opposite directions, their relative speed is $(x + 60)\, km/h$.To c

Vedclass · Accepted Answer

$90$

Vedclass · Answer

(B) Let the speed of the second train be $x\, km/h$.Since the trains are moving in opposite directions, their relative speed is $(x + 60)\, km/h$.To convert the relative speed into $m/s$, we multiply by $\frac{5}{18}$:Relative speed $= (x + 60) 	imes \frac{5}{18}\, m/s$.The total distance to be covered is the sum of the lengths of both trains:Total distance $= 180\, m + 270\, m = 450\, m$.Using the formula $	ext{Distance} = 	ext{Speed} 	imes 	ext{Time}$:$450 = (x + 60) 	imes \frac{5}{18} 	imes 10.8$.$450 = (x + 60) 	imes 5 	imes 0.6$.$450 = (x + 60) 	imes 3$.$150 = x + 60$.$x = 150 - 60 = 90\, km/h$.

$A$ $180\, m$ long train crosses another $270\, m$ long train running in the opposite direction in $10.8\, seconds$. If the speed of the first train is $60\, km/h$, what is the speed of the second train in $km/h$?

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