$A$ $110 \; V, 50 \; Hz, AC$ source is connected in the circuit (as shown in figure). The current through the resistance $55 \; \Omega$,at resonance in the circuit,will be $\dots \; A$.

At what angular frequency $\omega$ does the following circuit consume maximum power? (in $rad/s$)

The total impedance of a series $L-C-R$ circuit varies with the angular frequency of the $AC$ source connected to it,as shown in the graph. The quality factor $Q$ of the series $L-C-R$ circuit is:

An $AC$ circuit consists of an inductor of inductance $0.5 \, H$ and a capacitor of capacitance $8 \, \mu F$ in series. The current in the circuit is maximum when the angular frequency of the $AC$ source is

$A$ series $LCR$ circuit containing a resistance of $120\,\Omega$ has a resonance frequency of $4 \times 10^5\, rad\, s^{-1}$. The voltages,at resonance,across the resistance and inductance are $60\,V$ and $40\,V$ respectively. The values of $L$ and $C$ respectively are:

$A$ series $LCR$ circuit contains inductance $5 \ mH$,capacitance $2 \ \mu F$,and resistance $10 \ \Omega$. If the frequency of the $A.C.$ source is varied,what is the frequency at which maximum power is dissipated?