$A$ $10\, cm$ long wire is placed horizontally on the surface of water and is gently pulled up with a force of $2 \times 10^{-2}\, N$ to keep the wire in equilibrium. The surface tension,in $N/m$,of water is:

$A$ ring is cut from a platinum tube with an internal diameter of $8.5\, cm$ and an external diameter of $8.7\, cm$. It is supported horizontally from the pan of a balance so that it comes in contact with the water in a glass vessel. If an extra $3.97\, g$ weight is required to pull it away from the water,the surface tension of water is ......... $dyne\, cm^{-1}$.

Oil spreads over the surface of water whereas water does not spread over the surface of the oil,due to

$A$ square frame of each side $L$ is dipped in a soap solution and taken out. The force acting on the film formed is ($T =$ surface tension of soap solution). (in $TL$)

With an increase in temperature,surface tension of liquid (except molten copper and cadmium)

$A$ straw of circular cross-section of radius $R$ and negligible thickness is dipped vertically into a liquid of surface tension $T$. If the contact angle between the liquid and the straw material is $53^{\circ}$, what is the force acting on the straw due to the surface tension of the liquid? (Given: $\cos 53^{\circ} = 0.6$)