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(D) The volume of a $1 \ ml$ pipette is $1 \ cm^3 = 10^{-6} \ m^3$.Assuming the diameter of a typical bacterium is approximately $1 \ \mu m$ $(10^{-6}

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$10^{12}$ bacteria

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(D) The volume of a $1 \ ml$ pipette is $1 \ cm^3 = 10^{-6} \ m^3$.Assuming the diameter of a typical bacterium is approximately $1 \ \mu m$ $(10^{-6} \ m)$,the volume of one bacterium is roughly $(10^{-6} \ m)^3 = 10^{-18} \ m^3$.To find the number of bacteria that can fit in the pipette,we divide the total volume by the volume of one bacterium:Number of bacteria $= \frac{10^{-6} \ m^3}{10^{-18} \ m^3} = 10^{12}$ bacteria.Thus,a $1 \ ml$ pipette can contain about $10^{12}$ bacteria.

Column-$I$	Column-$II$
$(1)$ Mesosome	$(a)$ Not a component of the endomembrane system
$(2)$ Peroxisome	$(b)$ Many ribosomes associated with a single $m-RNA$
$(3)$ Polysome	$(c)$ Single membrane-bound system
$(4)$ Lysosome	$(d)$ Infoldings of the cell membrane

$A$ $1 \ ml$ pipette can contain about

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