A 100, W bulb working on 200, V and a 200, W | vedclass

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(B) The resistance of a bulb is given by the formula $R = \frac{V^2}{P}$.For the first bulb: $R_1 = \frac{200^2}{100} = \frac{40000}{100} = 400\,\Omeg

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Maximum current ratings in the ratio of $1:4$

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(B) The resistance of a bulb is given by the formula $R = \frac{V^2}{P}$.For the first bulb: $R_1 = \frac{200^2}{100} = \frac{40000}{100} = 400\,\Omega$.For the second bulb: $R_2 = \frac{100^2}{200} = \frac{10000}{200} = 50\,\Omega$.The maximum current rating is given by $i = \frac{P}{V}$.For the first bulb: $i_1 = \frac{100}{200} = 0.5\, A$.For the second bulb: $i_2 = \frac{200}{100} = 2.0\, A$.The ratio of maximum current ratings is $\frac{i_1}{i_2} = \frac{0.5}{2.0} = \frac{1}{4}$.

$A$ $100\, W$ bulb working on $200\, V$ and a $200\, W$ bulb working on $100\, V$ have:

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