A 220, V and 800, W electric kettle and three | vedclass

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(B) The devices are connected in parallel to a $220\, V$ supply,which is the rated voltage for all devices.Total power consumed by the circuit is the

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$5.0$

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(B) The devices are connected in parallel to a $220\, V$ supply,which is the rated voltage for all devices.Total power consumed by the circuit is the sum of the power of the kettle and the three bulbs.$P_{	ext{total}} = P_{	ext{kettle}} + 3 	imes P_{	ext{bulb}}$$P_{	ext{total}} = 800\, W + 3 	imes 100\, W = 800\, W + 300\, W = 1100\, W$.Using the formula for power $P = V 	imes I$,where $V = 220\, V$:$I = \frac{P_{	ext{total}}}{V} = \frac{1100\, W}{220\, V} = 5.0\, A$.Therefore,the total current is $5.0\, A$.

$A$ $220\, V$ and $800\, W$ electric kettle and three $220\, V$ and $100\, W$ bulbs are connected in parallel. On connecting this combination with a $220\, V$ electric supply,the total current will be ................ $A$.

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