A 5,^{circ}text{C} rise in temperature is obs | vedclass

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(C) The heat produced in a conductor due to the flow of current is given by Joule's law of heating: $H = i^2Rt$.Since the rise in temperature $\Delta

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$20$

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(C) The heat produced in a conductor due to the flow of current is given by Joule's law of heating: $H = i^2Rt$.Since the rise in temperature $\Delta T$ is directly proportional to the heat produced $H$,we have $\Delta T \propto i^2$.Given that the initial rise in temperature $\Delta T_1 = 5\,^{\circ}	ext{C}$ for current $i_1 = i$.When the current is doubled,$i_2 = 2i$.The new rise in temperature $\Delta T_2$ is given by the ratio:$\frac{\Delta T_2}{\Delta T_1} = \left(\frac{i_2}{i_1}ight)^2 = \left(\frac{2i}{i}ight)^2 = 4$.Therefore,$\Delta T_2 = 4 	imes \Delta T_1 = 4 	imes 5\,^{\circ}	ext{C} = 20\,^{\circ}	ext{C}$.

$A$ $5\,^{\circ}\text{C}$ rise in temperature is observed in a conductor by passing a current. When the current is doubled the rise in temperature will be approximately ........... $^{\circ}\text{C}$

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