$5.0 \, A$ current is set up in an external circuit by a $6.0 \, V$ storage battery for $6.0 \, \text{minutes}$. The chemical energy of the battery is reduced by:

  • A
    $1.08 \times 10^{4} \, J$
  • B
    $1.08 \times 10^{-4} \, V$
  • C
    $1.8 \times 10^{4} \, J$
  • D
    $1.08 \times 10^{4} \, V$

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