A pi^0 meson at rest decays into 2 gamma rays | vedclass

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(B) Since the $\pi^0$ meson is initially at rest,its initial linear momentum is $0$.According to the law of conservation of linear momentum,the total

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The two $\gamma$ rays move in opposite directions.

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(B) Since the $\pi^0$ meson is initially at rest,its initial linear momentum is $0$.According to the law of conservation of linear momentum,the total final momentum of the system must also be $0$.Let the momenta of the two $\gamma$ rays be $\vec{p}_1$ and $\vec{p}_2$. Then,$\vec{p}_1 + \vec{p}_2 = 0$,which implies $\vec{p}_1 = -\vec{p}_2$.This indicates that the two $\gamma$ rays must move in exactly opposite directions to ensure the total momentum remains $0$.

$A$ $\pi^0$ meson at rest decays into $2$ $\gamma$ rays: $\pi^0 \to \gamma + \gamma$. Which of the following must happen?

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