A bag contains 600 coins of 25 paise and 1200 | vedclass

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(C) Total money in the bag initially:$600 	imes 0.25 + 1200 	imes 0.50 = 150 + 600 = ₹ 750$.Amount of money removed:Money removed from $25$ paise co

Vedclass · Accepted Answer

$21.6$

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(C) Total money in the bag initially:$600 	imes 0.25 + 1200 	imes 0.50 = 150 + 600 = ₹ 750$.Amount of money removed:Money removed from $25$ paise coins $= 12 \% 	ext{ of } 150 = \frac{12}{100} 	imes 150 = ₹ 18$.Money removed from $50$ paise coins $= 24 \% 	ext{ of } 600 = \frac{24}{100} 	imes 600 = ₹ 144$.Total money removed $= 18 + 144 = ₹ 162$.Percentage of money removed:$	ext{Percentage} = \left( \frac{162}{750} ight) 	imes 100 = \frac{16200}{750} = 21.6 \%$.

$A$ bag contains $600$ coins of $25$ paise and $1200$ coins of $50$ paise. If $12 \%$ of $25$ paise coins and $24 \%$ of $50$ paise coins are removed,the percentage of money removed from the bag is nearly: (in $\%$)

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