A bag contains 3 red,4 white and 5 black ball | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Total number of balls $= 3 + 4 + 5 = 12$.Number of ways to draw $3$ balls out of $12$ is given by $^{12}C_3 = \frac{12 	imes 11 	imes 10}{3 	im

Vedclass · Accepted Answer

$\frac{3}{11}$

Vedclass · Answer

(A) Total number of balls $= 3 + 4 + 5 = 12$.Number of ways to draw $3$ balls out of $12$ is given by $^{12}C_3 = \frac{12 	imes 11 	imes 10}{3 	imes 2 	imes 1} = 220$.For the balls to be of different colours,we must draw $1$ red,$1$ white,and $1$ black ball.Number of favorable outcomes $= ^3C_1 	imes ^4C_1 	imes ^5C_1 = 3 	imes 4 	imes 5 = 60$.Probability $= \frac{	ext{Favorable outcomes}}{	ext{Total outcomes}} = \frac{60}{220} = \frac{6}{22} = \frac{3}{11}$.

$A$ bag contains $3$ red,$4$ white and $5$ black balls. Three balls are drawn at random. The probability of the balls being of different colours is

Similar Questions

Three unbiased coins are tossed once. What is the probability of getting at most two heads?

In a single throw of $2$ dice,find the probability of getting a total of $11$.

$2$ dice are thrown. Find the odds in favour of getting the sum $5$.

When two dice are thrown simultaneously,what is the probability that the numbers appeared on both dice are equal?

Among $15$ players,$8$ are batsmen and $7$ are bowlers. Find the probability that a team is chosen of $6$ batsmen and $5$ bowlers.

Vedclass Test Series

Exam Paper Generator

Online Exam Module