A bag contains 5 brown and 4 white socks. A m | vedclass

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(D) Total number of socks $= 5 + 4 = 9$.The total number of ways to select $2$ socks out of $9$ is given by $^9C_2 = \frac{9 	imes 8}{2 	imes 1} = 3

Vedclass · Accepted Answer

$\frac{48}{108}$

Vedclass · Answer

(D) Total number of socks $= 5 + 4 = 9$.The total number of ways to select $2$ socks out of $9$ is given by $^9C_2 = \frac{9 	imes 8}{2 	imes 1} = 36$.The number of ways to select $2$ brown socks from $5$ is $^5C_2 = \frac{5 	imes 4}{2 	imes 1} = 10$.The number of ways to select $2$ white socks from $4$ is $^4C_2 = \frac{4 	imes 3}{2 	imes 1} = 6$.The number of ways to select $2$ socks of the same colour is $10 + 6 = 16$.Therefore,the probability $P$ that both socks are of the same colour is $P = \frac{16}{36}$.To match the options,we multiply the numerator and denominator by $3$: $P = \frac{16 	imes 3}{36 	imes 3} = \frac{48}{108}$.

$Face$	$1$	$2$	$3$	$4$	$5$	$6$
$Probability$	$0.2$	$0.22$	$0.11$	$0.25$	$0.05$	$0.17$

$A$ bag contains $5$ brown and $4$ white socks. $A$ man pulls out two socks. The probability that these are of the same colour is

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