$A$ bag contains $30$ balls numbered from $1$ to $30$. One ball is drawn randomly. The probability that the number on the ball is a multiple of $5$ or $7$ is:

  • A
    $\frac{1}{2}$
  • B
    $\frac{1}{3}$
  • C
    $\frac{2}{3}$
  • D
    $\frac{1}{4}$

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Let $A = \{n \in N : H.C.F.(n, 45) = 1\}$ and $B = \{2k : k \in \{1, 2, \ldots, 100\}\}$. Then the sum of all the elements of $A \cap B$ is

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