$A$ bag contains $4$ white and $3$ red balls. Two draws of one ball each are made without replacement. Then the probability that both the balls are red is

  • A
    $\frac{1}{7}$
  • B
    $\frac{2}{7}$
  • C
    $\frac{3}{7}$
  • D
    $\frac{4}{7}$

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