A ball is suspended on a thread from the ceil | vedclass

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Question

(A) The car is decelerating,so it experiences a pseudo force in the forward direction. The deceleration $a$ is given by the change in velocity divided

Vedclass · Accepted Answer

$	heta = 	an^{-1} \left( \frac{1}{9} ight)$

Vedclass · Answer

(A) The car is decelerating,so it experiences a pseudo force in the forward direction. The deceleration $a$ is given by the change in velocity divided by time.$a = \frac{v_f - v_i}{t} = \frac{5/3 - 5}{3} = \frac{-10/3}{3} = -\frac{10}{9} \, m/s^2$.The magnitude of deceleration is $|a| = \frac{10}{9} \, m/s^2$.In the frame of the car,the ball experiences a pseudo force $F_p = ma$ acting forward and gravity $mg$ acting downward.The angle $	heta$ with the vertical is given by $	an 	heta = \frac{F_p}{mg} = \frac{ma}{mg} = \frac{a}{g}$.Taking $g = 10 \, m/s^2$,we get $	an 	heta = \frac{10/9}{10} = \frac{1}{9}$.Therefore,$	heta = 	an^{-1} \left( \frac{1}{9} ight)$.

$A$ ball is suspended on a thread from the ceiling of a car. The brakes are applied and the speed of the car changes from $5 \, m/s$ to $5/3 \, m/s$ during a time interval of $3 \, s$. Find the angle $\theta$ that the thread will deviate from the vertical.

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