$A$ ball of mass $m_1$ and another ball of mass $m_2$ are dropped from equal height. If the time taken by the balls are $t_1$ and $t_2$ respectively,then:

  • A
    $t_1 = \frac{t_2}{2}$
  • B
    $t_1 = t_2$
  • C
    $t_1 = 4t_2$
  • D
    $t_1 = \frac{t_2}{4}$

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