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(A) The object is dropped from the balloon,so its initial velocity is the same as the balloon's velocity,$u = 10 \, m/s$ (upwards).Taking the upward d

Vedclass · Accepted Answer

$125$

Vedclass · Answer

(A) The object is dropped from the balloon,so its initial velocity is the same as the balloon's velocity,$u = 10 \, m/s$ (upwards).Taking the upward direction as positive,the displacement of the object when it hits the ground is $s = -75 \, m$.The acceleration due to gravity is $a = -g = -10 \, m/s^2$.Using the equation of motion $s = ut + \frac{1}{2}at^2$:$-75 = 10t + \frac{1}{2}(-10)t^2$$-75 = 10t - 5t^2$$5t^2 - 10t - 75 = 0$$t^2 - 2t - 15 = 0$$(t - 5)(t + 3) = 0$Since time cannot be negative,$t = 5 \, s$.In this time,the balloon continues to move upwards with a uniform velocity of $10 \, m/s$.The distance covered by the balloon in $5 \, s$ is $d = v 	imes t = 10 	imes 5 = 50 \, m$.The height of the balloon from the ground when the object strikes the ground is $H = 75 + 50 = 125 \, m$.

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