(C) In a series circuit,the current remains the same through all components. According to Ohm's law,the current $I$ is given by $I = \frac{V}{R_{eq}}$

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(C) In a series circuit,the current remains the same through all components. According to Ohm's law,the current $I$ is given by $I = \frac{V}{R_{eq}}$.The equivalent resistance $R_{eq}$ for resistors connected in series is the sum of individual resistances:$R_{eq} = 0.2 + 0.3 + 0.4 + 0.5 + 12 = 13.4 \, \Omega$.Given the potential difference $V = 9 \, V$,the current is:$I = \frac{9}{13.4} \approx 0.671 \, A$.Thus,the current flowing through the $12 \, \Omega$ resistor is approximately $0.67 \, A$.

Class 10 Science Electricity Textbook - Electricity

Difficult

$A$ battery of $9 \, V$ is connected in series with resistors of $0.2 \, \Omega$,$0.3 \, \Omega$,$0.4 \, \Omega$,$0.5 \, \Omega$,and $12 \, \Omega$ respectively. How much current (in $A$) would flow through the $12 \, \Omega$ resistor?

A
$1.33$
B
$1.67$
C
$0.67$
D
$0.33$

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$A$ battery of $9 \, V$ is connected in series with resistors of $0.2 \, \Omega$,$0.3 \, \Omega$,$0.4 \, \Omega$,$0.5 \, \Omega$,and $12 \, \Omega$ respectively. How much current (in $A$) would flow through the $12 \, \Omega$ resistor?

Similar Questions

$A$ copper wire has a diameter of $0.5\, mm$ and a resistivity of $1.6 \times 10^{-8}\, \Omega \, m$. What will be the length of this wire to make its resistance $10\, \Omega$? How much does the resistance change if the diameter is doubled?

When a $12\, V$ battery is connected across an unknown resistor,there is a current of $2.5\, mA$ in the circuit. Find the value of the resistance of the resistor.

Two conducting wires of the same material and of equal lengths and equal diameters are first connected in series and then parallel in a circuit across the same potential difference. The ratio of heat produced in series and parallel combinations would be -

Why does the cord of an electric heater not glow while the heating element does?

Compare the power used in the $2 \,\Omega$ resistor in each of the following circuits: $(i)$ a $6 \,V$ battery in series with $1 \,\Omega$ and $2 \,\Omega$ resistors,and $(ii)$ a $4 \,V$ battery in parallel with $12 \,\Omega$ and $2 \,\Omega$ resistors.

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