A beam of light of lambda = 600 , nm from a d | vedclass

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(D) Given: $\lambda = 600 \, nm = 600 	imes 10^{-9} \, m$,slit width $a = 1 \, mm = 10^{-3} \, m$,and distance $D = 2 \, m$.The distance between the

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$2.4 \, mm$

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(D) Given: $\lambda = 600 \, nm = 600 	imes 10^{-9} \, m$,slit width $a = 1 \, mm = 10^{-3} \, m$,and distance $D = 2 \, m$.The distance between the first dark fringes on either side of the central bright fringe is equal to the width of the central maximum.The formula for the width of the central maximum is given by $w = \frac{2 \lambda D}{a}$.Substituting the values:$w = \frac{2 	imes (600 	imes 10^{-9} \, m) 	imes 2 \, m}{10^{-3} \, m}$$w = \frac{2400 	imes 10^{-9}}{10^{-3}} \, m$$w = 2400 	imes 10^{-6} \, m = 2.4 	imes 10^{-3} \, m = 2.4 \, mm$.

$A$ beam of light of $\lambda = 600 \, nm$ from a distant source falls on a single slit $1 \, mm$ wide and the resulting diffraction pattern is observed on a screen $2 \, m$ away. The distance between the first dark fringes on either side of the central bright fringe is:

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