A beam of light of wavelength 600, nm from a | vedclass

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(D) The distance between the first dark fringes on either side of the central bright fringe is equal to the width of the central maximum.The formula f

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$2.4\, mm$

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(D) The distance between the first dark fringes on either side of the central bright fringe is equal to the width of the central maximum.The formula for the width of the central maximum in a single-slit diffraction pattern is given by $w = \frac{2\lambda D}{d}$.Given:$\lambda = 600\, nm = 600 	imes 10^{-9}\, m$$d = 1\, mm = 1 	imes 10^{-3}\, m$$D = 2\, m$Substituting the values:$w = \frac{2 	imes 600 	imes 10^{-9} 	imes 2}{1 	imes 10^{-3}}$$w = \frac{2400 	imes 10^{-9}}{10^{-3}}$$w = 2400 	imes 10^{-6}\, m = 2.4 	imes 10^{-3}\, m = 2.4\, mm$.Therefore, the correct option is $D$.

$A$ beam of light of wavelength $600\, nm$ from a distant source falls on a single slit $1\, mm$ wide and the resulting diffraction pattern is observed on a screen $2\, m$ away. The distance between the first dark fringes on either side of the central bright fringe is

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