A biconvex lens with equal radii of curvature | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The lens maker's formula is given by: $\frac{1}{f} = (\mu - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right)$.For a biconvex lens with equal radii

Vedclass · Accepted Answer

$12$

Vedclass · Answer

(D) The lens maker's formula is given by: $\frac{1}{f} = (\mu - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} ight)$.For a biconvex lens with equal radii of curvature,we have $R_1 = R$ and $R_2 = -R$.Substituting these values into the formula: $\frac{1}{f} = (\mu - 1) \left( \frac{1}{R} - \frac{1}{-R} ight) = (\mu - 1) \left( \frac{2}{R} ight)$.Given $f = 10 \ cm$ and $\mu = 1.6$,we have: $\frac{1}{10} = (1.6 - 1) \left( \frac{2}{R} ight)$.$\frac{1}{10} = (0.6) \left( \frac{2}{R} ight) = \frac{1.2}{R}$.Therefore,$R = 1.2 	imes 10 = 12 \ cm$.

$A$ biconvex lens with equal radii of curvature has a refractive index of $1.6$ and a focal length of $10 \ cm$. Its radius of curvature will be.......$cm$.

Similar Questions

An object is located in a fixed position in front of a screen. $A$ sharp image is obtained on the screen for two positions of a thin lens separated by $10\, cm$. The size of the images in the two situations are in the ratio $3 : 2$. What is the distance between the screen and the object in $cm$?

An object is placed on the axis of a convex lens. Its image is formed $80 \, cm$ from the object. The magnification is $3$. The focal length of the lens is.....$cm$

$A$ thin lens made of glass of refractive index $\mu_g = 1.5$ has a focal length of $12 \ cm$ in air. If it is immersed in water of refractive index $\mu_w = 4/3$,what will be its new focal length in $cm$?

$A$ convex lens forming a real image of magnification $m_1$ on a screen is moved through a distance $x$. $A$ new image of magnification $m_2$ is again formed on the screen. The focal length of the lens is:

$A$ convex lens of focal length $f$ produces an image $\frac{1}{n}$ times the size of the object. The distance of the object from the lens is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module