(C) Assuming the volume of the tyre remains constant,we use Gay-Lussac's Law: $\frac{P_1}{T_1} = \frac{P_2}{T_2}$.Given:$P_1 = 270\,kPa$$T_1 = 27^{\ci

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(C) Assuming the volume of the tyre remains constant,we use Gay-Lussac's Law: $\frac{P_1}{T_1} = \frac{P_2}{T_2}$.Given:$P_1 = 270\,kPa$$T_1 = 27^{\circ}C = 27 + 273 = 300\,K$$T_2 = 36^{\circ}C = 36 + 273 = 309\,K$Substituting the values:$P_2 = \frac{P_1 \times T_2}{T_1} = \frac{270 \times 309}{300}$.$P_2 = 0.9 \times 309 = 278.1\,kPa$.Rounding to the nearest integer,the pressure is $278\,kPa$.

Class 11 Physics Kinetic Theory of Gases Gas Laws (Charles, Boyle's, Avagadro's, Gay Lussacs and Dalton's law) and Ideal gas Equation

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$A$ bicycle tyre is filled with air having pressure of $270\,kPa$ at $27^{\circ}C$. The approximate pressure of the air in the tyre when the temperature increases to $36^{\circ}C$ is $............kPa$.

JEE MAIN 2023 All JEE MAIN

A
$270$
B
$262$
C
$278$
D
$360$

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Kinetic Theory of Gases

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Gas Laws (Charles, Boyle's, Avagadro's, Gay Lussacs and Dalton's law) and Ideal gas Equation

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$A$ bicycle tyre is filled with air having pressure of $270\,kPa$ at $27^{\circ}C$. The approximate pressure of the air in the tyre when the temperature increases to $36^{\circ}C$ is $............kPa$.

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