A black sulphide precipitate when treated wit | vedclass

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Question

(D) The black sulphide precipitate is lead$(II)$ sulphide $(PbS)$.When $PbS$ is treated with ozone $(O_3)$,it undergoes oxidation to form lead$(II)$ s

Vedclass · Accepted Answer

$PbSO_4$

Vedclass · Answer

(D) The black sulphide precipitate is lead$(II)$ sulphide $(PbS)$.When $PbS$ is treated with ozone $(O_3)$,it undergoes oxidation to form lead$(II)$ sulphate $(PbSO_4)$,which is a white compound.The balanced chemical equation is:$PbS + 4O_3 \rightarrow PbSO_4 + 4O_2$(Black) $\rightarrow$ (White)Therefore,the correct option is $D$.

$A$ black sulphide precipitate when treated with ozone becomes white. The white compound is:

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