A block of ice at -20,^oC having a mass of 2, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Heat required to raise the temperature of $2\,kg$ of ice from $-20\,^oC$ to $0\,^oC$ is $Q_1 = m_i c_i \Delta T = 2000\,g 	imes 0.5\,cal/g^oC 	i

Vedclass · Accepted Answer

The final temperature will be $0\,^oC$.

Vedclass · Answer

(A) Heat required to raise the temperature of $2\,kg$ of ice from $-20\,^oC$ to $0\,^oC$ is $Q_1 = m_i c_i \Delta T = 2000\,g 	imes 0.5\,cal/g^oC 	imes 20\,^oC = 20,000\,cal$.Heat available from cooling $3\,kg$ of water from $15\,^oC$ to $0\,^oC$ is $Q_2 = m_w c_w \Delta T = 3000\,g 	imes 1\,cal/g^oC 	imes 15\,^oC = 45,000\,cal$.Remaining heat available after warming the ice to $0\,^oC$ is $Q_{rem} = Q_2 - Q_1 = 45,000 - 20,000 = 25,000\,cal$.Heat required to melt the entire $2\,kg$ of ice at $0\,^oC$ is $Q_3 = m_i L_f = 2000\,g 	imes 80\,cal/g = 160,000\,cal$.Since $Q_{rem} < Q_3$,the available heat is not sufficient to melt all the ice. Therefore,the system will reach thermal equilibrium at $0\,^oC$ with a mixture of ice and water.

$A$ block of ice at $-20\,^oC$ having a mass of $2\,kg$ is added to $3\,kg$ of water at $15\,^oC$. Neglecting heat losses and the heat capacity of the container,what is the final state of the system?

Similar Questions

Of two masses of $5 \, kg$ each falling from a height of $10 \, m$,by which $2 \, kg$ of water is stirred. The rise in temperature of the water will be ........ $^\circ C$.

If $540 \, g$ of ice at $0^{\circ}C$ is mixed with $540 \, g$ of water at $80^{\circ}C$,what will be the final temperature of the mixture in $^{\circ}C$?

$200 \, g$ of a solid ball at $20 \, ^oC$ is dropped into an equal amount of water at $80 \, ^oC$. The resulting temperature is $60 \, ^oC$. This means that the specific heat of the solid is

$10\,g$ of ice at $-20\,^{\circ}C$ is dropped into a calorimeter containing $10\,g$ of water at $10\,^{\circ}C$. The specific heat of water is twice that of ice. When equilibrium is reached,the calorimeter will contain

An iron ball of mass $0.2\,kg$ is heated to $100\,^{\circ}C$ and put into a block of ice at $0\,^{\circ}C.$ If $25\,g$ of ice melts,and the latent heat of fusion of ice is $80\,cal/g,$ find the specific heat of iron in $cal/g\,^{\circ}C.$

Vedclass Test Series

Exam Paper Generator

Online Exam Module