$A$ block of mass $m$ slides down on a wedge of mass $M$ as shown in the figure. Let $\vec a_1$ be the acceleration of the wedge and $\vec a_2$ be the acceleration of the block with respect to the ground. $N_1$ is the normal reaction between the block and the wedge,and $N_2$ is the normal reaction between the wedge and the ground. Friction is absent everywhere. Select the incorrect alternative.

  • A
    $N_2 < (M + m)g$
  • B
    $N_1 = m(g \cos \theta - |\vec a_1| \sin \theta)$
  • C
    $N_1 \sin \theta = M|\vec a_1|$
  • D
    $m\vec a_2 = -M\vec a_1$

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