A block of mass 10 , kg is placed on a rough | vedclass

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(B) Given: Mass $m = 10 \, kg$,coefficient of friction $\mu = 0.5$,applied force $F = 100 \, N$,and acceleration due to gravity $g = 10 \, m/s^2$.Firs

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$5$

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(B) Given: Mass $m = 10 \, kg$,coefficient of friction $\mu = 0.5$,applied force $F = 100 \, N$,and acceleration due to gravity $g = 10 \, m/s^2$.First,calculate the limiting friction force: $f_k = \mu \cdot m \cdot g = 0.5 	imes 10 	imes 10 = 50 \, N$.Since the applied force $F = 100 \, N$ is greater than the limiting friction $f_k = 50 \, N$,the block will move.The net force acting on the block is $F_{net} = F - f_k = 100 - 50 = 50 \, N$.Using Newton's second law,$F_{net} = m \cdot a$,the acceleration $a = \frac{F_{net}}{m} = \frac{50}{10} = 5 \, m/s^2$.

$A$ block of mass $10 \, kg$ is placed on a rough horizontal surface having a coefficient of friction $\mu = 0.5$. If a horizontal force of $100 \, N$ is acting on it,then the acceleration of the block will be ....... $m/s^2$.

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