$A$ body,thrown upwards with some velocity,reaches a maximum height of $50 \,m$. Another body with double the mass,thrown up with double the initial velocity,will reach a maximum height of............$m$.

With what speed should a body be thrown upwards so that the distances traversed in the $5^{\text{th}}$ second and $6^{\text{th}}$ second are equal? (Take $g = 9.8 \, m/s^2$)

$A$ body projected vertically upwards crosses a point twice in its journey at a height $h$ after $t_1$ and $t_2$ seconds. The maximum height reached by the body is

The vertical height of point $P$ above the ground is twice that of $Q$. $A$ particle is projected downward with a speed of $5 \, m/s$ from $P$ and at the same time another particle is projected upward with the same speed from $Q$. Both particles reach the ground simultaneously,then:

$A$ student is throwing balls vertically upwards such that he throws the $2^{\text{nd}}$ ball when the $1^{\text{st}}$ ball reaches its maximum height. If he throws balls at an interval of $3 \ s$,what is the maximum height reached by the balls (in $m$)? (Take $g = 10 \ m/s^2$)

$A$ body projected vertically upwards with a velocity $u$ returns to the starting point in $4 \, s$. If $g = 10 \, m/s^2$,the value of $u$ is $......... \, m/s$.