A body is falling from a height h. After it h | vedclass

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(A) According to the Law of Conservation of Energy,the total mechanical energy of a freely falling body remains constant.At height $h$,the potential e

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half potential and half kinetic energy

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(A) According to the Law of Conservation of Energy,the total mechanical energy of a freely falling body remains constant.At height $h$,the potential energy $(PE)$ is $mgh$ and kinetic energy $(KE)$ is $0$.After falling a distance of $\frac{h}{2}$,the remaining height is $\frac{h}{2}$.The potential energy at this point is $PE = mg(\frac{h}{2}) = \frac{1}{2}mgh$.Since the total energy is $mgh$,the kinetic energy must be $KE = mgh - \frac{1}{2}mgh = \frac{1}{2}mgh$.Therefore,at half the height,the body possesses half potential energy and half kinetic energy.

$A$ body is falling from a height $h$. After it has fallen a height $\frac{h}{2}$,it will possess

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