(D) The centripetal force is given by the formula $F_c = \frac{mv^2}{r}$.Since the speed $v$ remains constant,the mass $m$ is constant,and the radius

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(D) The centripetal force is given by the formula $F_c = \frac{mv^2}{r}$.Since the speed $v$ remains constant,the mass $m$ is constant,and the radius $r$ of the circular path remains the same,the magnitude of the centripetal force remains unchanged.The centripetal force is always directed towards the center of the circle,regardless of whether the body moves clockwise or counter-clockwise.Therefore,reversing the direction of motion does not change the magnitude or the direction of the centripetal force.Thus,both statements $(a)$ and $(c)$ are correct.

Class 11 Physics 3-2.Motion in Plane Mix Examples-Motion in Plane

Easy

$A$ body is revolving with a constant speed along a circle. If its direction of motion is reversed but the speed remains the same,then which of the following statements is true?

A
The centripetal force will not suffer any change in magnitude.
B
The centripetal force will have its direction reversed.
C
The centripetal force will not suffer any change in direction.
D
Both $(a)$ and $(c)$.

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3-2.Motion in Plane

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Mix Examples-Motion in Plane

Will the linear velocity of a particle rotating with a constant angular speed about a non-fixed axis be constant? Why?

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$A$ block of mass $5 \, kg$ is moving with a horizontal velocity of $1.5 \, m/s$. $A$ force of $5 \, N$ is applied in the perpendicular (vertical) direction for $4 \, s$. The total distance covered by the block is .......... $m$.

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The displacement vector of a particle of mass $m$ is given by $\vec{r}(t) = A \cos \omega t \hat{i} + B \sin \omega t \hat{j}$.
$(a)$ Show that the trajectory is an ellipse.
$(b)$ Show that $\vec{F} = -m \omega^2 \vec{r}$.

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$A$ particle of mass $m$ is projected at a velocity $u$, making an angle $\theta$ with the horizontal ($x$-axis). If the angle of projection $\theta$ is varied keeping all other parameters same, then the magnitude of angular momentum $(L)$ at its maximum height about the point of projection varies with $\theta$ as,

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$A$ particle of mass $m$ moves along a circular path of constant radius $r$. The centripetal acceleration of the particle $a_c$ varies with time $t$ as $a_c = k^2rt^2$,where $k$ is a constant. What is the power delivered to the particle by the force acting on it?

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$A$ body is revolving with a constant speed along a circle. If its direction of motion is reversed but the speed remains the same,then which of the following statements is true?

Similar Questions

Will the linear velocity of a particle rotating with a constant angular speed about a non-fixed axis be constant? Why?

$A$ block of mass $5 \, kg$ is moving with a horizontal velocity of $1.5 \, m/s$. $A$ force of $5 \, N$ is applied in the perpendicular (vertical) direction for $4 \, s$. The total distance covered by the block is .......... $m$.

The displacement vector of a particle of mass $m$ is given by $\vec{r}(t) = A \cos \omega t \hat{i} + B \sin \omega t \hat{j}$.$(a)$ Show that the trajectory is an ellipse.$(b)$ Show that $\vec{F} = -m \omega^2 \vec{r}$.

$A$ particle of mass $m$ moves along a circular path of constant radius $r$. The centripetal acceleration of the particle $a_c$ varies with time $t$ as $a_c = k^2rt^2$,where $k$ is a constant. What is the power delivered to the particle by the force acting on it?

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The displacement vector of a particle of mass $m$ is given by $\vec{r}(t) = A \cos \omega t \hat{i} + B \sin \omega t \hat{j}$.
$(a)$ Show that the trajectory is an ellipse.
$(b)$ Show that $\vec{F} = -m \omega^2 \vec{r}$.