A body of mass 1,kg crosses a point O with a | vedclass

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Question

(B) Given: mass $m = 1\,kg$,initial velocity $u = 60\,ms^{-1}$,force $F = -10\,N$ (directed towards $O$,opposite to motion).Acceleration $a = \frac{F}

Vedclass · Accepted Answer

$12$

Vedclass · Answer

(B) Given: mass $m = 1\,kg$,initial velocity $u = 60\,ms^{-1}$,force $F = -10\,N$ (directed towards $O$,opposite to motion).Acceleration $a = \frac{F}{m} = \frac{-10}{1} = -10\,ms^{-2}$.To find the time taken to return to point $O$,the displacement $s$ must be $0$.Using the equation of motion $s = ut + \frac{1}{2}at^2$:$0 = 60t + \frac{1}{2}(-10)t^2$$0 = 60t - 5t^2$$5t^2 = 60t$Since $t 
eq 0$,we divide by $5t$:$t = \frac{60}{5} = 12\,s$.Thus,the body will again cross $O$ in $12\,s$.

$A$ body of mass $1\,kg$ crosses a point $O$ with a velocity $60\,ms^{-1}$. $A$ force of $10\,N$ directed towards $O$ begins to act on it. It will again cross $O$ in ......... $\sec$.

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