A body of mass 2, kg moving with a velocity o | vedclass

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(C) According to the law of conservation of linear momentum,the total momentum before the collision is equal to the total momentum after the collision

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$2/3$

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(C) According to the law of conservation of linear momentum,the total momentum before the collision is equal to the total momentum after the collision.Let the mass of the first body be $m_1 = 2\, kg$ and its velocity be $u_1 = 3\, m/s$.Let the mass of the second body be $m_2 = 1\, kg$ and its velocity be $u_2 = -4\, m/s$ (since it is moving in the opposite direction).Let the common velocity after the collision be $v$.Using the conservation of momentum: $m_1 u_1 + m_2 u_2 = (m_1 + m_2) v$.Substituting the values: $(2 	imes 3) + (1 	imes -4) = (2 + 1) v$.$6 - 4 = 3v$.$2 = 3v$.$v = 2/3\, m/s$.

$A$ body of mass $2\, kg$ moving with a velocity of $3\, m/s$ collides head-on with a body of mass $1\, kg$ moving in the opposite direction with a velocity of $4\, m/s$. After the collision,the two bodies stick together and move with a common velocity. The common velocity in $m/s$ is equal to:

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