A body of mass 5, kg is placed at the origin | vedclass

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(D) The work done by a constant force is given by the formula $W = F S \cos 	heta$,where $F$ is the magnitude of the force,$S$ is the displacement,an

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$20$

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(D) The work done by a constant force is given by the formula $W = F S \cos 	heta$,where $F$ is the magnitude of the force,$S$ is the displacement,and $	heta$ is the angle between the force vector and the displacement vector.Given:Force $F = 10\, N$Displacement $S = 4\, m$Angle $	heta = 60^\circ$Substituting these values into the formula:$W = 10 	imes 4 	imes \cos 60^\circ$Since $\cos 60^\circ = 0.5$,we have:$W = 10 	imes 4 	imes 0.5 = 20\, J$.Therefore,the work done by the force is $20\, J$.

$A$ body of mass $5\, kg$ is placed at the origin and can move only on the $x$-axis. $A$ force of $10\, N$ is acting on it in a direction making an angle of $60^\circ$ with the $x$-axis and displaces it along the $x$-axis by $4\, m$. The work done by the force is $...\, J$.

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