A body of mass 5, kg moving with a velocity 1 | vedclass

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Question

(A) According to the law of conservation of linear momentum,the total momentum before the collision is equal to the total momentum after the collision

Vedclass · Accepted Answer

$2.5$

Vedclass · Answer

(A) According to the law of conservation of linear momentum,the total momentum before the collision is equal to the total momentum after the collision.Let $m_1 = 5\, kg$,$u_1 = 10\, m/s$,$m_2 = 20\, kg$,and $u_2 = 0\, m/s$.After the collision,the first body comes to rest,so $v_1 = 0\, m/s$. Let the velocity of the second body be $v_2$.Using the conservation of momentum formula:$m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2$Substituting the values:$(5 	imes 10) + (20 	imes 0) = (5 	imes 0) + (20 	imes v_2)$$50 + 0 = 0 + 20 v_2$$50 = 20 v_2$$v_2 = \frac{50}{20} = 2.5\, m/s$.Therefore,the velocity of the second body is $2.5\, m/s$.

$A$ body of mass $5\, kg$ moving with a velocity $10\, m/s$ collides with another body of mass $20\, kg$ at rest and comes to rest. The velocity of the second body after the collision is ......... $m/s$.

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