A body of mass 8,kg and another of mass 2,kg | vedclass

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(B) The kinetic energy $K$ and momentum $P$ are related by the formula $K = \frac{P^2}{2m}$,which implies $P = \sqrt{2mK}$.Given that the kinetic ener

Vedclass · Accepted Answer

$2:1$

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(B) The kinetic energy $K$ and momentum $P$ are related by the formula $K = \frac{P^2}{2m}$,which implies $P = \sqrt{2mK}$.Given that the kinetic energies are equal $(K_1 = K_2 = K)$,the ratio of their momenta is:$\frac{P_1}{P_2} = \frac{\sqrt{2m_1K}}{\sqrt{2m_2K}} = \sqrt{\frac{m_1}{m_2}}$.Substituting the given masses $m_1 = 8\,kg$ and $m_2 = 2\,kg$:$\frac{P_1}{P_2} = \sqrt{\frac{8}{2}} = \sqrt{4} = 2$.Thus,the ratio is $2:1$.

$A$ body of mass $8\,kg$ and another of mass $2\,kg$ are moving with equal kinetic energy. The ratio of their respective momenta will be.

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