(D) The magnitude of acceleration in simple harmonic motion is given by the formula $|a| = \omega^2 y$,where $a$ is acceleration,$\omega$ is angular f

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(D) The magnitude of acceleration in simple harmonic motion is given by the formula $|a| = \omega^2 y$,where $a$ is acceleration,$\omega$ is angular frequency,and $y$ is displacement.Given $a = 1.0 \, m/s^2$ and $y = 0.01 \, m$,we have:$1.0 = \omega^2 \times 0.01$$\omega^2 = \frac{1.0}{0.01} = 100$$\omega = 10 \, rad/s$The time period $T$ is related to angular frequency by $T = \frac{2\pi}{\omega}$.Substituting the value of $\omega$:$T = \frac{2\pi}{10} = \frac{\pi}{5} \, s$.

Class 11 Physics Oscillations Acceleration and Force of Simple Harmonic Motion

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$A$ body oscillates with a simple harmonic motion having amplitude $0.05 \, m$. At a certain instant,its displacement is $0.01 \, m$ and acceleration is $1.0 \, m/s^2$. The period of oscillation is

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A
$0.1 \, s$
B
$0.2 \, s$
C
$\frac{\pi}{10} \, s$
D
$\frac{\pi}{5} \, s$

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Acceleration and Force of Simple Harmonic Motion

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$A$ body oscillates with a simple harmonic motion having amplitude $0.05 \, m$. At a certain instant,its displacement is $0.01 \, m$ and acceleration is $1.0 \, m/s^2$. The period of oscillation is

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