A body starts with an initial velocity of 10, | vedclass

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(A) Let the initial velocity be $u = 10\,m/s$ and the acceleration be $a$. Let the displacement when the velocity becomes $v_1 = 50\,m/s$ be $s$.Using

Vedclass · Accepted Answer

$70$

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(A) Let the initial velocity be $u = 10\,m/s$ and the acceleration be $a$. Let the displacement when the velocity becomes $v_1 = 50\,m/s$ be $s$.Using the equation of motion $v^2 = u^2 + 2as$:$(50)^2 = (10)^2 + 2as$$2500 = 100 + 2as$$2as = 2400$Now,the acceleration is reversed,so the new acceleration is $-a$. The particle travels from the point where $v = 50\,m/s$ back to the starting point,covering a displacement of $-s$.Using the equation of motion $v_f^2 = v_i^2 + 2a's'$:$v_f^2 = (50)^2 + 2(-a)(-s)$$v_f^2 = 2500 + 2as$Substitute $2as = 2400$ into the equation:$v_f^2 = 2500 + 2400 = 4900$$v_f = \sqrt{4900} = 70\,m/s$.

$A$ body starts with an initial velocity of $10\,m/s$ and moves along a straight line with constant acceleration. When the velocity of the particle is $50\,m/s$,the acceleration is reversed in direction. The velocity of the particle when it again reaches the starting point is $............\,m/s$.

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