A body weighs 700 , gm , wt on the surface of | vedclass

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(B) The acceleration due to gravity on the surface of the earth is $g = \frac{GM_e}{R_e^2}$.On the surface of the planet,the mass is $M_p = \frac{M_e}

Vedclass · Accepted Answer

$400$

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(B) The acceleration due to gravity on the surface of the earth is $g = \frac{GM_e}{R_e^2}$.On the surface of the planet,the mass is $M_p = \frac{M_e}{7}$ and the radius is $R_p = \frac{R_e}{2}$.The acceleration due to gravity on the planet is $g' = \frac{GM_p}{R_p^2} = \frac{G(M_e/7)}{(R_e/2)^2} = \frac{G M_e / 7}{R_e^2 / 4} = \frac{4}{7} \frac{GM_e}{R_e^2} = \frac{4}{7} g$.The weight of the body on the planet is $w' = m g' = m \left( \frac{4}{7} g ight) = \frac{4}{7} (mg) = \frac{4}{7} 	imes 700 \, gm \, wt = 400 \, gm \, wt$.

$A$ body weighs $700 \, gm \, wt$ on the surface of the earth. How much will it weigh on the surface of a planet whose mass is $\frac{1}{7}$ and radius is half that of the earth?

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