A bomb at rest explodes into three fragments | vedclass

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(D) According to the law of conservation of linear momentum,the initial momentum of the system is zero because the bomb is at rest. Therefore,the vect

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They fly with different speeds in different directions in a plane

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(D) According to the law of conservation of linear momentum,the initial momentum of the system is zero because the bomb is at rest. Therefore,the vector sum of the momenta of the three fragments must be zero: $\vec{p}_X + \vec{p}_Y + \vec{p}_Z = 0$. Since each fragment has the same mass $m$,we can write $m\vec{v}_X + m\vec{v}_Y + m\vec{v}_Z = 0$,which simplifies to $\vec{v}_X + \vec{v}_Y + \vec{v}_Z = 0$. This vector equation implies that the three velocity vectors must form a closed triangle. For three vectors to sum to zero,they must lie in the same plane. Since the fragments are moving in a plane,they will generally move with different velocities (speeds and directions) to satisfy the condition that their vector sum is zero.

$A$ bomb at rest explodes into three fragments $X, Y$ and $Z$. Each one of them has the same mass. Which of the following correctly describes the motion of the fragments?

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