A boy stands straight in front of a mirror at | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The magnification $m$ is given by the ratio of the height of the image to the height of the object,which is $m = \frac{h_i}{h_o} = \frac{1}{5}$.Si

Vedclass · Accepted Answer

Convex mirror

Vedclass · Answer

(B) The magnification $m$ is given by the ratio of the height of the image to the height of the object,which is $m = \frac{h_i}{h_o} = \frac{1}{5}$.Since the image is erect,the magnification is positive $(m = +0.2)$.$A$ plane mirror always produces an image of the same size $(m = 1)$,so it is not a plane mirror.$A$ concave mirror can produce an erect image only when the object is placed between the pole and the focus,but in that case,the image is always magnified $(m > 1)$.$A$ convex mirror always forms a virtual,erect,and diminished image for all positions of the object.Therefore,the mirror must be a convex mirror.

$A$ boy stands straight in front of a mirror at a distance of $30 \ cm$ away from it. He sees his erect image whose height is $\frac{1}{5}$ of his real height. The mirror he is using is

Similar Questions

An object is placed at a distance of $10 \, cm$ from a concave mirror of focal length $20 \, cm$. The image formed will be .......

In an experiment to find the focal length of a concave mirror,a graph is drawn between the magnitudes of $u$ and $v$. The graph looks like:

Define the centre of curvature for a convex mirror.

The field of view is maximum for

$A$ candle flame of $3\, cm$ is placed at $3\, m$ from a wall. $A$ concave mirror is kept at a distance $x$ from the wall in such a way that the image of the flame on the wall is $9\, cm$. Then $x$ is......$cm$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module