A boy takes as much time in running 12 , m as | vedclass

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Question

(A) Let the speed of the boy be $v_b$ and the speed of the car be $v_c$.Since the time taken $t$ is the same for both,we use the formula $	ext{speed}

Vedclass · Accepted Answer

$1:3$

Vedclass · Answer

(A) Let the speed of the boy be $v_b$ and the speed of the car be $v_c$.Since the time taken $t$ is the same for both,we use the formula $	ext{speed} = \frac{	ext{distance}}{	ext{time}}$,which implies $	ext{time} = \frac{	ext{distance}}{	ext{speed}}$.Given that the time taken is equal:$\frac{12}{v_b} = \frac{36}{v_c}$Rearranging the terms to find the ratio of speeds $\frac{v_b}{v_c}$:$\frac{v_b}{v_c} = \frac{12}{36}$$\frac{v_b}{v_c} = \frac{1}{3}$Therefore,the ratio of the speeds of the boy and the car is $1:3$.

$A$ boy takes as much time in running $12 \, m$ as a car takes in covering $36 \, m$. The ratio of the speeds of the boy and the car is

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