$A$ brown ring is formed in the ring test for $NO_{3}^{-}$ ion. It is due to the formation of :-

  • A
    $[Fe(H_{2}O)_{5}(NO)]^{2+}$
  • B
    $[Fe(H_{2}O)_{4}(NO)_{2}]^{2+}$
  • C
    $FeSO_{4} \cdot NO_{2}$
  • D
    $FeSO_{4} \cdot HNO_{3}$

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